题意:~
思路:先处理出乘坐出租车能到达的点,建图跑最短路即可。
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int MAXN = 100010;
const LL INF = 1e18 + 7;
const int lowINF = 0x3f3f3f3f;
struct Edge
{
int v;
LL cost;
Edge(int _v = 0, LL _cost = 0): v(_v), cost(_cost) {}
};
vector<Edge>E[MAXN];
vector<Edge>G[MAXN];
void addedge(int u, int v, LL w)
{
E[u].push_back(Edge(v, w));
}
void addeg(int u, int v, LL w)
{
G[u].push_back(Edge(v, w));
}
bool vis[MAXN];
int cnt[MAXN];
LL dist[MAXN];
bool SPFA(int start, int n)
{
memset(vis, false, sizeof(vis));
for(int i = 1; i <= n; i++)dist[i] = INF;
vis[start] = true;
dist[start] = 0;
queue<int>que;
while(!que.empty())que.pop();
que.push(start);
memset(cnt, 0, sizeof(cnt));
cnt[start] = 1;
while(!que.empty())
{
int u = que.front();
que.pop();
vis[u] = false;
for(int i = 0; i < E[u].size(); i++)
{
int v = E[u][i].v;
if(dist[v] > dist[u] + E[u][i].cost)
{
dist[v] = dist[u] + E[u][i].cost;
if(!vis[v])
{
vis[v] = true;
que.push(v);
if(++cnt[v] > n)return false;
}
}
}
}
return true;
}
bool mk[1050];
//cost len st u
void fd(LL cost, LL len, int st, int u)
{
if(!len) return;
for(LL i = 0; i < G[u].size(); i++)
{
LL v = G[u][i].v;
LL w = G[u][i].cost;
if(w <= len && !mk[v])
{
addedge(st, v, cost);
mk[v] = 1;
fd(cost, len - w, st, v);
}
}
}
map<int, map<int, int > >mp;
int gg[1010][1010];
int main()
{
int n, m;
cin >> n >> m;
int st, ed;
cin >> st >> ed;
int u, v, w;
memset(gg, lowINF, sizeof(gg));
for(int i = 0; i < m; ++i)
{
scanf("%d%d%d", &u, &v, &w);
if(w < gg[u][v])
{
gg[u][v] = w;
gg[v][u] = w;
}
}
for(int i = 1; i <= n; ++i)
{
for(int j = i + 1; j <= n; ++j)
{
if(gg[i][j] != lowINF)
{
addeg(i, j, gg[i][j]);
addeg(j, i, gg[i][j]);
}
}
}
int x, c;
for(int i = 1; i <= n; ++i)
{
scanf("%d%d", &x, &c);
memset(mk, 0, sizeof(mk));
mk[i] = 1;
fd(c, x, i, i);
}
SPFA(st, n);
if(dist[ed] == INF) cout << "-1" << endl;
else cout << dist[ed] << endl;
return 0;
}
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